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What is 8 to the power of 0?

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When raising a non-zero number to the power of zero, the result is always one. This principle is rooted in the properties of exponents. Specifically, for any non-zero number \( a \), the expression \( a^0 \) evaluates to 1.

To understand this further, consider the sequence of powers for the base of 8:

- \( 8^3 = 512 \)

- \( 8^2 = 64 \)

- \( 8^1 = 8 \)

As you reduce the exponent by 1 each time, you are essentially dividing by the base (in this case, 8):

- \( 8^2 \div 8 = 8^1 \)

- \( 8^1 \div 8 = 8^0 \)

Continuing this pattern, when you decrease from \( 8^1 \) to \( 8^0 \), you are dividing by 8:

- \( 8^1 = 8 \) and \( 8^0 = 8 \div 8 = 1 \)

Thus, we see that no matter what the base is (as long as it isn't zero), raising it to the power of

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